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k in (-oo:+oo)
(5/3)*k^2-k-(6/5) = 0
(5/3)*k^2-k-6/5 = 0
5/3*k^2-k-6/5 = 0
DELTA = (-1)^2-(-6/5*5/3*4)
DELTA = 9
DELTA > 0
k = (9^(1/2)+1)/(5/3*2) or k = (1-9^(1/2))/(5/3*2)
k = 6/5 or k = -3/5
k in { -3/5, 6/5 }
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